### Given the circuit diagram below, write a C program that calculates the following:

- The potential difference across x
- The charge on z
- The energy on y

**Source Code**

Brief explanation is provided after the source code.

#include <stdio.h> #include <math.h> int main(void){ float Cx = 3e-6, Cy = 2e-6, Cz = 4e-6, Cp, Ct, q, Vx, Vz, Wy; int v = 6; Cp = Cy + Cz; // capacitance in parallel Ct = (Cx * Cp) / (Cx + Cp); // total capacitance q = Ct * v; // compute charge Vx = q / Cx; // p.d across x Vz = v - Vx; // p.d across z Wy = 0.5 * Cy * pow(Vz, 2); // energy on y printf("Potential difference across x: %.1fV\n", Vx); printf("Charge on z: %0.1eC\n", Cz * Vz); printf("Energy on y: %0.1eJ\n", Wy); return 0; }

When you compile and execute the above program it produces the following result on Linux:

Potential difference across x: 4.0V Charge on z: 8.0e-06C Energy on y: 4.0e-06J

**Brief Explanation**

- The program starts by calculating the capacitance of the capacitors in parallel and the total capacitance of the circuit.
- The charge q is computed by multiplying the total capacitance with the voltage in the circuit.
- The potential difference across x is computed by dividing the charge q by the capacitance at x.
- The potential difference at z is computed by subtracting the potential difference at x from the voltage of the circuit.
- The charge on z is computed by multiplying the capacitance at z with the potential difference at z.
- The energy on y is computed using the formula, 1/2CyVy
^{2}and Vy = Vz. - Using printf function, the results are printed to the stdout.